304=4x^2+70x

Solution for 304=4x^2+70x equation:

304=4x^2+70x

We move all terms to the left:

304-(4x^2+70x)=0

We get rid of parentheses

-4x^2-70x+304=0

a = -4; b = -70; c = +304;
Δ = b2-4ac
Δ = -702-4·(-4)·304
Δ = 9764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9764}=\sqrt{4*2441}=\sqrt{4}*\sqrt{2441}=2\sqrt{2441}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-2\sqrt{2441}}{2*-4}=\frac{70-2\sqrt{2441}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+2\sqrt{2441}}{2*-4}=\frac{70+2\sqrt{2441}}{-8}
$